![]() ![]() Giberson thought of Thunderbird while he was drinking his morning coffee in a cup with a two-headed bird. Maybe uninspired at the time, Ford decided to run a competition within his company find a suitable name for the 2-seater. 1 / 65 View More Description Rebuilt 390 Partial RestoratFord Thunderbird The fourth generation Thunderbird was produced by Ford from 1964 thru 1966. Interestingly, the name of Thunderbird was chosen by a Ford stylist named Alden Giberson. Unexpectedly, the Thunderbird proved to be even more successful than the Corvette, only due to an impressive marketing strategy: the Thunderbird was advertised as a personal luxury car as opposed to the Corvette which was marketed as a sports car. ![]() Once it was shown to the public, the orders started flowing - over 3,500 order in the first ten days. Seeing the painted clay model, Crusoe was impressed and got Henry’s approval for the final design. It was Hershey’s idea to design the new car based on his favourite sports cars, the Jaguar XK120, thus, the Thunderbird was built on the same platform, featuring similar interior seating position, steering wheel angle and pedal angles. Crusoe worked along with Ford’s chief designed, Frank Hershey. Henry Ford II got in touch with Lewis Crusoe, a former GM executive, and asked him to help them develop the new car. Ford’s response to the Chevrolet Corvette, the Ford Thunderbird was unveiled to the public toward the end of 1954 at the Detroit Auto Show.įord realised that the new Corvette was of a great importance in the car industry and had to provide a swift response. ![]()
0 Comments
![]() Initial velocity is both vertical and horizontal Use trig functions to find vyi and vx vx = vi Cos θ vyi = vi Sin θ Remember clues vy at the top is 0 m/s vy at any height is the same while going up and coming down except for direction ∆y = 0 m if ending at the same height as it startedĨ Example Problem Happy Gilmore hits his shot at 55.0 m/s with an angle of 50.0° to the ground. Treat horizontal and vertical as two separate sides of the problems TIME is the key, and the only variable that can be used for both horizontal and vertical Horizontal Motion is always constant vx is constant ax = 0 m/s2 Objects follow a parabolic shape ay = g = m/s2Īll of the initial velocity is in the x direction, vyi = 0 m/s Vertical displacement and velocity will always be negative ![]() Figure 3.36 illustrates the notation for displacement, where s s size 12 takes a positive value.Presentation on theme: "Projectile Motion Horizontal Angular."- Presentation transcript: (This choice of axes is the most sensible, because acceleration due to gravity is vertical-thus, there will be no acceleration along the horizontal axis when air resistance is negligible.) As is customary, we call the horizontal axis the x-axis and the vertical axis the y-axis. The key to analyzing two-dimensional projectile motion is to break it into two motions, one along the horizontal axis and the other along the vertical. This fact was discussed in Kinematics in Two Dimensions: An Introduction, where vertical and horizontal motions were seen to be independent. The most important fact to remember here is that motions along perpendicular axes are independent and thus can be analyzed separately. ![]() In this section, we consider two-dimensional projectile motion, such as that of a football or other object for which air resistance is negligible. The motion of falling objects, as covered in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of projectile motion in which there is no horizontal movement. The object is called a projectile, and its path is called its trajectory. Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. 3.A.1.3 The student is able to analyze experimental data describing the motion of an object and is able to express the results of the analysis using narrative, mathematical, and graphical representations.3.A.1.1 The student is able to express the motion of an object using narrative, mathematical, and graphical representations.The information presented in this section supports the following AP® learning objectives: Apply the principle of independence of motion to solve projectile motion problems. ![]() ![]() Determine the location and velocity of a projectile at different points in its trajectory.Identify and explain the properties of a projectile, such as acceleration due to gravity, range, maximum height, and trajectory.By the end of this section, you will be able to: ![]() |